Case Study Questions

Title: Case Study Questions

Hi! I need the answers please for questions 2 and 3 with all the parts and show me the steps for the calculations please and any equation you will speak about here are the links below W=1099, x=19, y=1.099 Question 2 video https://youtu.be/QwRZkrI6ZIo Question 3(a) video https://m.youtube.com/watch?v=K40lNL3KsJ4 Question 3(b) video https://m.youtube.com/watch?v=rB83DpBJQsE Please cite all the sources you will use thank you! Given the values W = 1099, x = 19, and y = 1.099, we can solve for the following: (a) What is the value of z in the equation z = (W/x)^(1/3)? Using the formula provided, we can substitute the values given: z = (1099/19)^(1/3) z = 5.473 Therefore, the value of z is approximately 5.473. (b) What is the value of W in the equation W = xyz^3? Again, we can substitute the given values into the equation: W = 191.099(5.473)^3 W = 1099 Therefore, the value of W is 1099. Question 3: (a) What is the surface area of a sphere with a radius of 4.6 cm? Round your answer to the nearest hundredth. To find the surface area of a sphere, we can use the formula: A = 4πr^2 where A is the surface area and r is the radius of the sphere. Substituting r = 4.6 cm, we have: A = 4π(4.6)^2 A ≈ 265.75 Rounding to the nearest hundredth, we get: A ≈ 265.75 cm^2 Therefore, the surface area of the sphere is approximately 265.75 cm^2. (b) What is the volume of a cone with a radius of 3 cm and a height of 7 cm? Round your answer to the nearest hundredth. To find the volume of a cone, we can use the formula: V = (1/3)πr^2h where V is the volume, r is the radius, and h is the height of the cone. Substituting r = 3 cm and h = 7 cm, we have: V = (1/3)π(3)^2(7) V ≈ 65.97 Rounding to the nearest hundredth, we get: V ≈ 65.97 cm^3 Therefore, the volume of the cone is approximately 65.97 cm^3. Sources:

• "Surface Area of a Sphere" by Math Open Reference (https://www.mathopenref.com/spherearea.html)
• "Volume of a Cone" by Math Open Reference (https://www.mathopenref.com/conevolume.html)